You can use itertools.chain for this:

list1 = [['str1', 'str2', 'str3'],
        [['str4', 'str5'], 'str6', 'str7', 'str8'],
        ['str9', 'str10']]

from itertools import chain

def listy(x):
    return x if isinstance(x, list) else [x]

for sublist in list1:
    print(' '.join(chain.from_iterable(map(listy, sublist))))

str1 str2 str3
str4 str5 str6 str7 str8
str9 str10

11. Lists, You can use itertools.chain for this: list1 = [['str1', 'str2', 'str3'], [['str4', 'str5'], 'str6', '​str7', 'str8'], ['str9', 'str10']] from itertools import chain def  Lists and strings — and other collections that maintain the order of their items Each time through the loop, the variable i is used as an index into the list, printing the i'th Although a list can contain another list, the nested list still counts as a single Since variables refer to objects, if we assign one variable to another, both 

Use a recursive function to deal with any depth of sub-lists, but make the printing of newline characters after each sub-list optional and only enable it at the first call.

list1 = [ ['str1', 'str2', 'str3'],
        [['str4', 'str5'], 'str6', 'str7', 'str8'],
        ['str9', 'str10']]
def p(l, newline=True):
    output = ''
    for i in l:
        if isinstance(i, str):
            output += i + ' '
        else:
            p(i, False)
            if newline:
                print()
    print(output, end='')
p(list1)

This outputs:

str1 str2 str3 
str4 str5 str6 str7 str8 
str9 str10 

nested list python, Nested List Comprehensions in Python filter_none edit close play_arrow link brightness_4 code. But in our case, the expression itself is a list comprehension. edit close. play_arrow. link brightness_4 code. But in our case, the expression itself is a list comprehension. Hence expression = [0, Nested List Comprehensions in Python filter_none edit close play_arrow link brightness_4 code. But in our case, the expression itself is a list comprehension. edit close. play_arrow. link brightness_4 code. But in our case, the expression itself is a list comprehension. Hence expression = [0,

Firstly, you need to loop through the first inner layer then flatten the elements inside it.

Then print it in order with join function. Detail below.

list1 = [ ['str1', 'str2', 'str3'],
        [['str4', 'str5'], 'str6', 'str7', 'str8'],
        ['str9', 'str10']]

def flatten(lst):
    if lst==[]:
        return lst
    else:
        if isinstance(list[0], list):
            return flatten(lst[0])+flatten(lst[1:])
        else:
            return [lst[0],]+flatten(lst[1:])

def print_it(lst_rino):
    for lst in lst_rino:
        new_lst=flatten(lst)
        print(" ".join(new_lst))

print_it(list1)

The Output:

str1 str2 str3
str4 str5 str6 str7 str8
str9 str10

python list of lists, It is quite easy to create list of lists in Python. You just need to use list’s append method to create list of lists. Here is simple example to create list of lists in Python. list1= [1,2,3,4] list2= [5,6,7,8] listoflists= [] listoflists.append (list1) listoflists.append (list2) print ("List of Lists:",listoflists) script.py. It is quite easy to create list of lists in Python. You just need to use list’s append method to create list of lists. Here is simple example to create list of lists in Python. list1= [1,2,3,4] list2= [5,6,7,8] listoflists= [] listoflists.append (list1) listoflists.append (list2) print ("List of Lists:",listoflists) script.py.

Still new to python but cant this be solved with simple string concatenation and list elements?

something along the lines of

list1 = [['str1', 'str2', 'str3'],[['str4', 'str5'], 'str6', 'str7', 'str8'],['str9', 'str10']]

print(str(list1[0]) + '\n' + str(list1[1]) + '\n' + str(list1[2]))

output is exactly what op asked for?

['str1', 'str2', 'str3']
[['str4', 'str5'], 'str6', 'str7', 'str8']
['str9', 'str10']

create list of lists python, That will create a list (a type of mutable array in python) called my_list with the output of the np.getfromtext () method in the first 2 indexes. Just came across the same issue today In order to create a list of lists you will have firstly to store your data, array, or other type of variable into a list. That will create a list (a type of mutable array in python) called my_list with the output of the np.getfromtext () method in the first 2 indexes. Just came across the same issue today In order to create a list of lists you will have firstly to store your data, array, or other type of variable into a list.